Java program determine if year leap year


















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HansHirse 16k 10 10 gold badges 28 28 silver badges 53 53 bronze badges. Miguel Landy Miguel Landy 1. In the Julian calendar, leap years are divisible by 4 while in the Gregorian calendar, leap years are either of the following: Divisible by Divisible by 4 and not divisible by Sanket Mathur Sanket Mathur 29 2 2 silver badges 7 7 bronze badges.

Wasn't aware of this OOTB method — anubhava. Tribhuwan Tribhuwan 1 1 gold badge 1 1 silver badge 11 11 bronze badges. Tribhuwan DarenW is correct. Your answer is incorrect. The Overflow Blog. Then it prints is a leap year. Then that static method starts the execution.

Integer is the wrapper class which converts the string into int data type. The methods used in this case are: Using Ternary Operator. Using Static Method. A century year is a leap year only if it is divisible by A leap year except a century year can be identified if it is exactly divisible by 4.

A century year should be divisible by 4 and both. A non-century year should be divisible only by 4. Without Using Scanner Class As the name suggests here user is bound not to select a year of his choice. Skip to content. Change Language. This is checked using a if else statement. To understand this example, you should have the knowledge of the following Java programming topics:. A leap year is exactly divisible by 4 except for century years years ending with The century year is a leap year only if it is perfectly divisible by In the above example, we are checking if the year is a leap year or not.

Since is a century year ending with 00 , it should be divisible by both 4 and to be a leap year. Here, is not a century year. Hence, to be a leap year, it needs to be divisible by only 4. Course Index Explore Programiz. Java for Loop. Arrays in Java. Interfaces in Java.



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